Integrand size = 31, antiderivative size = 205 \[ \int \frac {\sec (e+f x) (c+d \sec (e+f x))^4}{(a+a \sec (e+f x))^3} \, dx=\frac {(4 c-3 d) d^3 \text {arctanh}(\sin (e+f x))}{a^3 f}+\frac {(c-d) (2 c+9 d) (c+d \sec (e+f x))^2 \tan (e+f x)}{15 a f (a+a \sec (e+f x))^2}+\frac {(c-d) (c+d \sec (e+f x))^3 \tan (e+f x)}{5 f (a+a \sec (e+f x))^3}+\frac {\left (2 c^4+8 c^3 d+21 c^2 d^2-88 c d^3+72 d^4-d^2 \left (2 c^2+10 c d-27 d^2\right ) \sec (e+f x)\right ) \tan (e+f x)}{15 f \left (a^3+a^3 \sec (e+f x)\right )} \]
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Time = 0.41 (sec) , antiderivative size = 265, normalized size of antiderivative = 1.29, number of steps used = 7, number of rules used = 7, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.226, Rules used = {4072, 100, 155, 148, 65, 223, 209} \[ \int \frac {\sec (e+f x) (c+d \sec (e+f x))^4}{(a+a \sec (e+f x))^3} \, dx=\frac {\tan (e+f x) \left (2 c^4+8 c^3 d-d^2 \left (2 c^2+10 c d-27 d^2\right ) \sec (e+f x)+21 c^2 d^2-88 c d^3+72 d^4\right )}{15 f \left (a^3 \sec (e+f x)+a^3\right )}+\frac {2 d^3 (4 c-3 d) \tan (e+f x) \arctan \left (\frac {\sqrt {a-a \sec (e+f x)}}{\sqrt {a (\sec (e+f x)+1)}}\right )}{a^2 f \sqrt {a-a \sec (e+f x)} \sqrt {a \sec (e+f x)+a}}+\frac {(c-d) \tan (e+f x) (c+d \sec (e+f x))^3}{5 f (a \sec (e+f x)+a)^3}+\frac {(c-d) (2 c+9 d) \tan (e+f x) (c+d \sec (e+f x))^2}{15 a f (a \sec (e+f x)+a)^2} \]
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Rule 65
Rule 100
Rule 148
Rule 155
Rule 209
Rule 223
Rule 4072
Rubi steps \begin{align*} \text {integral}& = -\frac {\left (a^2 \tan (e+f x)\right ) \text {Subst}\left (\int \frac {(c+d x)^4}{\sqrt {a-a x} (a+a x)^{7/2}} \, dx,x,\sec (e+f x)\right )}{f \sqrt {a-a \sec (e+f x)} \sqrt {a+a \sec (e+f x)}} \\ & = \frac {(c-d) (c+d \sec (e+f x))^3 \tan (e+f x)}{5 f (a+a \sec (e+f x))^3}+\frac {\tan (e+f x) \text {Subst}\left (\int \frac {(c+d x)^2 \left (-a^2 \left (2 c^2+6 c d-3 d^2\right )+a^2 (c-6 d) d x\right )}{\sqrt {a-a x} (a+a x)^{5/2}} \, dx,x,\sec (e+f x)\right )}{5 a f \sqrt {a-a \sec (e+f x)} \sqrt {a+a \sec (e+f x)}} \\ & = \frac {(c-d) (2 c+9 d) (c+d \sec (e+f x))^2 \tan (e+f x)}{15 a f (a+a \sec (e+f x))^2}+\frac {(c-d) (c+d \sec (e+f x))^3 \tan (e+f x)}{5 f (a+a \sec (e+f x))^3}+\frac {\tan (e+f x) \text {Subst}\left (\int \frac {(c+d x) \left (-a^4 \left (2 c^3+8 c^2 d+23 c d^2-18 d^3\right )+a^4 d \left (2 c^2+10 c d-27 d^2\right ) x\right )}{\sqrt {a-a x} (a+a x)^{3/2}} \, dx,x,\sec (e+f x)\right )}{15 a^4 f \sqrt {a-a \sec (e+f x)} \sqrt {a+a \sec (e+f x)}} \\ & = \frac {(c-d) (2 c+9 d) (c+d \sec (e+f x))^2 \tan (e+f x)}{15 a f (a+a \sec (e+f x))^2}+\frac {(c-d) (c+d \sec (e+f x))^3 \tan (e+f x)}{5 f (a+a \sec (e+f x))^3}+\frac {\left (2 c^4+8 c^3 d+21 c^2 d^2-88 c d^3+72 d^4-d^2 \left (2 c^2+10 c d-27 d^2\right ) \sec (e+f x)\right ) \tan (e+f x)}{15 f \left (a^3+a^3 \sec (e+f x)\right )}-\frac {\left ((4 c-3 d) d^3 \tan (e+f x)\right ) \text {Subst}\left (\int \frac {1}{\sqrt {a-a x} \sqrt {a+a x}} \, dx,x,\sec (e+f x)\right )}{a f \sqrt {a-a \sec (e+f x)} \sqrt {a+a \sec (e+f x)}} \\ & = \frac {(c-d) (2 c+9 d) (c+d \sec (e+f x))^2 \tan (e+f x)}{15 a f (a+a \sec (e+f x))^2}+\frac {(c-d) (c+d \sec (e+f x))^3 \tan (e+f x)}{5 f (a+a \sec (e+f x))^3}+\frac {\left (2 c^4+8 c^3 d+21 c^2 d^2-88 c d^3+72 d^4-d^2 \left (2 c^2+10 c d-27 d^2\right ) \sec (e+f x)\right ) \tan (e+f x)}{15 f \left (a^3+a^3 \sec (e+f x)\right )}+\frac {\left (2 (4 c-3 d) d^3 \tan (e+f x)\right ) \text {Subst}\left (\int \frac {1}{\sqrt {2 a-x^2}} \, dx,x,\sqrt {a-a \sec (e+f x)}\right )}{a^2 f \sqrt {a-a \sec (e+f x)} \sqrt {a+a \sec (e+f x)}} \\ & = \frac {(c-d) (2 c+9 d) (c+d \sec (e+f x))^2 \tan (e+f x)}{15 a f (a+a \sec (e+f x))^2}+\frac {(c-d) (c+d \sec (e+f x))^3 \tan (e+f x)}{5 f (a+a \sec (e+f x))^3}+\frac {\left (2 c^4+8 c^3 d+21 c^2 d^2-88 c d^3+72 d^4-d^2 \left (2 c^2+10 c d-27 d^2\right ) \sec (e+f x)\right ) \tan (e+f x)}{15 f \left (a^3+a^3 \sec (e+f x)\right )}+\frac {\left (2 (4 c-3 d) d^3 \tan (e+f x)\right ) \text {Subst}\left (\int \frac {1}{1+x^2} \, dx,x,\frac {\sqrt {a-a \sec (e+f x)}}{\sqrt {a+a \sec (e+f x)}}\right )}{a^2 f \sqrt {a-a \sec (e+f x)} \sqrt {a+a \sec (e+f x)}} \\ & = \frac {2 (4 c-3 d) d^3 \arctan \left (\frac {\sqrt {a-a \sec (e+f x)}}{\sqrt {a+a \sec (e+f x)}}\right ) \tan (e+f x)}{a^2 f \sqrt {a-a \sec (e+f x)} \sqrt {a+a \sec (e+f x)}}+\frac {(c-d) (2 c+9 d) (c+d \sec (e+f x))^2 \tan (e+f x)}{15 a f (a+a \sec (e+f x))^2}+\frac {(c-d) (c+d \sec (e+f x))^3 \tan (e+f x)}{5 f (a+a \sec (e+f x))^3}+\frac {\left (2 c^4+8 c^3 d+21 c^2 d^2-88 c d^3+72 d^4-d^2 \left (2 c^2+10 c d-27 d^2\right ) \sec (e+f x)\right ) \tan (e+f x)}{15 f \left (a^3+a^3 \sec (e+f x)\right )} \\ \end{align*}
Time = 3.86 (sec) , antiderivative size = 292, normalized size of antiderivative = 1.42 \[ \int \frac {\sec (e+f x) (c+d \sec (e+f x))^4}{(a+a \sec (e+f x))^3} \, dx=\frac {2 \cos \left (\frac {1}{2} (e+f x)\right ) \left (3 (c-d)^4 \sec \left (\frac {e}{2}\right ) \sin \left (\frac {f x}{2}\right )-8 (c-d)^3 (2 c+3 d) \cos ^2\left (\frac {1}{2} (e+f x)\right ) \sec \left (\frac {e}{2}\right ) \sin \left (\frac {f x}{2}\right )+4 (c-d)^2 \left (7 c^2+26 c d+57 d^2\right ) \cos ^4\left (\frac {1}{2} (e+f x)\right ) \sec \left (\frac {e}{2}\right ) \sin \left (\frac {f x}{2}\right )-60 d^3 \cos ^5\left (\frac {1}{2} (e+f x)\right ) \left ((4 c-3 d) \left (\log \left (\cos \left (\frac {1}{2} (e+f x)\right )-\sin \left (\frac {1}{2} (e+f x)\right )\right )-\log \left (\cos \left (\frac {1}{2} (e+f x)\right )+\sin \left (\frac {1}{2} (e+f x)\right )\right )\right )-d \sec (e) \sec (e+f x) \sin (f x)\right )+3 (c-d)^4 \cos \left (\frac {1}{2} (e+f x)\right ) \tan \left (\frac {e}{2}\right )-8 (c-d)^3 (2 c+3 d) \cos ^3\left (\frac {1}{2} (e+f x)\right ) \tan \left (\frac {e}{2}\right )\right )}{15 a^3 f (1+\cos (e+f x))^3} \]
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Time = 0.94 (sec) , antiderivative size = 247, normalized size of antiderivative = 1.20
method | result | size |
parallelrisch | \(\frac {-960 \left (c -\frac {3 d}{4}\right ) \cos \left (f x +e \right ) d^{3} \ln \left (\tan \left (\frac {f x}{2}+\frac {e}{2}\right )-1\right )+960 \left (c -\frac {3 d}{4}\right ) \cos \left (f x +e \right ) d^{3} \ln \left (\tan \left (\frac {f x}{2}+\frac {e}{2}\right )+1\right )+29 \sec \left (\frac {f x}{2}+\frac {e}{2}\right )^{4} \tan \left (\frac {f x}{2}+\frac {e}{2}\right ) \left (\frac {6 \left (2 c^{4}+12 c^{3} d +12 c^{2} d^{2}-68 c \,d^{3}+57 d^{4}\right ) \cos \left (2 f x +2 e \right )}{29}+\frac {\left (7 c^{4}+12 c^{3} d +12 c^{2} d^{2}-88 c \,d^{3}+72 d^{4}\right ) \cos \left (3 f x +3 e \right )}{29}+\left (c^{4}+\frac {84}{29} c^{3} d +\frac {204}{29} c^{2} d^{2}-\frac {776}{29} c \,d^{3}+\frac {684}{29} d^{4}\right ) \cos \left (f x +e \right )+\frac {12 c^{4}}{29}+\frac {72 c^{3} d}{29}+\frac {72 c^{2} d^{2}}{29}-\frac {408 c \,d^{3}}{29}+\frac {402 d^{4}}{29}\right )}{240 f \,a^{3} \cos \left (f x +e \right )}\) | \(247\) |
derivativedivides | \(\frac {\frac {\tan \left (\frac {f x}{2}+\frac {e}{2}\right )^{5} c^{4}}{5}-\frac {4 \tan \left (\frac {f x}{2}+\frac {e}{2}\right )^{5} c^{3} d}{5}+\frac {6 \tan \left (\frac {f x}{2}+\frac {e}{2}\right )^{5} c^{2} d^{2}}{5}-\frac {4 \tan \left (\frac {f x}{2}+\frac {e}{2}\right )^{5} c \,d^{3}}{5}+\frac {\tan \left (\frac {f x}{2}+\frac {e}{2}\right )^{5} d^{4}}{5}-\frac {2 \tan \left (\frac {f x}{2}+\frac {e}{2}\right )^{3} c^{4}}{3}+4 \tan \left (\frac {f x}{2}+\frac {e}{2}\right )^{3} c^{2} d^{2}-\frac {16 \tan \left (\frac {f x}{2}+\frac {e}{2}\right )^{3} c \,d^{3}}{3}+2 \tan \left (\frac {f x}{2}+\frac {e}{2}\right )^{3} d^{4}+\tan \left (\frac {f x}{2}+\frac {e}{2}\right ) c^{4}+4 \tan \left (\frac {f x}{2}+\frac {e}{2}\right ) c^{3} d +6 \tan \left (\frac {f x}{2}+\frac {e}{2}\right ) c^{2} d^{2}-28 \tan \left (\frac {f x}{2}+\frac {e}{2}\right ) c \,d^{3}+17 \tan \left (\frac {f x}{2}+\frac {e}{2}\right ) d^{4}-\frac {4 d^{4}}{\tan \left (\frac {f x}{2}+\frac {e}{2}\right )+1}+4 d^{3} \left (4 c -3 d \right ) \ln \left (\tan \left (\frac {f x}{2}+\frac {e}{2}\right )+1\right )-\frac {4 d^{4}}{\tan \left (\frac {f x}{2}+\frac {e}{2}\right )-1}-4 d^{3} \left (4 c -3 d \right ) \ln \left (\tan \left (\frac {f x}{2}+\frac {e}{2}\right )-1\right )}{4 f \,a^{3}}\) | \(321\) |
default | \(\frac {\frac {\tan \left (\frac {f x}{2}+\frac {e}{2}\right )^{5} c^{4}}{5}-\frac {4 \tan \left (\frac {f x}{2}+\frac {e}{2}\right )^{5} c^{3} d}{5}+\frac {6 \tan \left (\frac {f x}{2}+\frac {e}{2}\right )^{5} c^{2} d^{2}}{5}-\frac {4 \tan \left (\frac {f x}{2}+\frac {e}{2}\right )^{5} c \,d^{3}}{5}+\frac {\tan \left (\frac {f x}{2}+\frac {e}{2}\right )^{5} d^{4}}{5}-\frac {2 \tan \left (\frac {f x}{2}+\frac {e}{2}\right )^{3} c^{4}}{3}+4 \tan \left (\frac {f x}{2}+\frac {e}{2}\right )^{3} c^{2} d^{2}-\frac {16 \tan \left (\frac {f x}{2}+\frac {e}{2}\right )^{3} c \,d^{3}}{3}+2 \tan \left (\frac {f x}{2}+\frac {e}{2}\right )^{3} d^{4}+\tan \left (\frac {f x}{2}+\frac {e}{2}\right ) c^{4}+4 \tan \left (\frac {f x}{2}+\frac {e}{2}\right ) c^{3} d +6 \tan \left (\frac {f x}{2}+\frac {e}{2}\right ) c^{2} d^{2}-28 \tan \left (\frac {f x}{2}+\frac {e}{2}\right ) c \,d^{3}+17 \tan \left (\frac {f x}{2}+\frac {e}{2}\right ) d^{4}-\frac {4 d^{4}}{\tan \left (\frac {f x}{2}+\frac {e}{2}\right )+1}+4 d^{3} \left (4 c -3 d \right ) \ln \left (\tan \left (\frac {f x}{2}+\frac {e}{2}\right )+1\right )-\frac {4 d^{4}}{\tan \left (\frac {f x}{2}+\frac {e}{2}\right )-1}-4 d^{3} \left (4 c -3 d \right ) \ln \left (\tan \left (\frac {f x}{2}+\frac {e}{2}\right )-1\right )}{4 f \,a^{3}}\) | \(321\) |
norman | \(\frac {\frac {\left (c^{4}-4 c^{3} d +6 c^{2} d^{2}-4 c \,d^{3}+d^{4}\right ) \tan \left (\frac {f x}{2}+\frac {e}{2}\right )^{13}}{20 a f}+\frac {\left (c^{4}+4 c^{3} d +6 c^{2} d^{2}-28 c \,d^{3}+25 d^{4}\right ) \tan \left (\frac {f x}{2}+\frac {e}{2}\right )}{4 a f}-\frac {\left (7 c^{4}+24 c^{3} d +30 c^{2} d^{2}-160 c \,d^{3}+135 d^{4}\right ) \tan \left (\frac {f x}{2}+\frac {e}{2}\right )^{3}}{6 a f}-\frac {\left (11 c^{4}-24 c^{3} d +6 c^{2} d^{2}+16 c \,d^{3}-9 d^{4}\right ) \tan \left (\frac {f x}{2}+\frac {e}{2}\right )^{11}}{30 a f}-\frac {\left (11 c^{4}+16 c^{3} d +6 c^{2} d^{2}-104 c \,d^{3}+81 d^{4}\right ) \tan \left (\frac {f x}{2}+\frac {e}{2}\right )^{7}}{5 a f}+\frac {\left (73 c^{4}-12 c^{3} d -42 c^{2} d^{2}-172 c \,d^{3}+153 d^{4}\right ) \tan \left (\frac {f x}{2}+\frac {e}{2}\right )^{9}}{60 a f}+\frac {\left (133 c^{4}+348 c^{3} d +318 c^{2} d^{2}-2212 c \,d^{3}+1773 d^{4}\right ) \tan \left (\frac {f x}{2}+\frac {e}{2}\right )^{5}}{60 a f}}{\left (\tan \left (\frac {f x}{2}+\frac {e}{2}\right )^{2}-1\right )^{4} a^{2}}+\frac {d^{3} \left (4 c -3 d \right ) \ln \left (\tan \left (\frac {f x}{2}+\frac {e}{2}\right )+1\right )}{a^{3} f}-\frac {d^{3} \left (4 c -3 d \right ) \ln \left (\tan \left (\frac {f x}{2}+\frac {e}{2}\right )-1\right )}{a^{3} f}\) | \(423\) |
risch | \(\frac {2 i \left (120 c^{2} d^{2} {\mathrm e}^{4 i \left (f x +e \right )}-668 c \,d^{3} {\mathrm e}^{2 i \left (f x +e \right )}+72 c^{3} d \,{\mathrm e}^{2 i \left (f x +e \right )}-300 c \,d^{3} {\mathrm e}^{5 i \left (f x +e \right )}-640 c \,d^{3} {\mathrm e}^{4 i \left (f x +e \right )}+60 c^{2} d^{2} {\mathrm e}^{i \left (f x +e \right )}-380 c \,d^{3} {\mathrm e}^{i \left (f x +e \right )}-60 c \,d^{3} {\mathrm e}^{6 i \left (f x +e \right )}+60 c^{3} d \,{\mathrm e}^{4 i \left (f x +e \right )}+60 c^{2} d^{2} {\mathrm e}^{3 i \left (f x +e \right )}-680 c \,d^{3} {\mathrm e}^{3 i \left (f x +e \right )}+132 c^{2} d^{2} {\mathrm e}^{2 i \left (f x +e \right )}+72 d^{4}+7 c^{4}+120 c^{3} d \,{\mathrm e}^{3 i \left (f x +e \right )}+60 c^{3} d \,{\mathrm e}^{i \left (f x +e \right )}+60 c^{3} d \,{\mathrm e}^{5 i \left (f x +e \right )}+225 d^{4} {\mathrm e}^{5 i \left (f x +e \right )}+315 d^{4} {\mathrm e}^{i \left (f x +e \right )}+567 d^{4} {\mathrm e}^{2 i \left (f x +e \right )}+15 c^{4} {\mathrm e}^{6 i \left (f x +e \right )}+600 d^{4} {\mathrm e}^{3 i \left (f x +e \right )}+480 d^{4} {\mathrm e}^{4 i \left (f x +e \right )}+20 c^{4} {\mathrm e}^{i \left (f x +e \right )}+45 d^{4} {\mathrm e}^{6 i \left (f x +e \right )}+47 c^{4} {\mathrm e}^{2 i \left (f x +e \right )}+55 c^{4} {\mathrm e}^{4 i \left (f x +e \right )}+12 c^{3} d +12 c^{2} d^{2}-88 c \,d^{3}+50 c^{4} {\mathrm e}^{3 i \left (f x +e \right )}+30 c^{4} {\mathrm e}^{5 i \left (f x +e \right )}\right )}{15 f \,a^{3} \left (1+{\mathrm e}^{2 i \left (f x +e \right )}\right ) \left ({\mathrm e}^{i \left (f x +e \right )}+1\right )^{5}}+\frac {4 d^{3} \ln \left ({\mathrm e}^{i \left (f x +e \right )}+i\right ) c}{a^{3} f}-\frac {3 d^{4} \ln \left ({\mathrm e}^{i \left (f x +e \right )}+i\right )}{a^{3} f}-\frac {4 d^{3} \ln \left ({\mathrm e}^{i \left (f x +e \right )}-i\right ) c}{a^{3} f}+\frac {3 d^{4} \ln \left ({\mathrm e}^{i \left (f x +e \right )}-i\right )}{a^{3} f}\) | \(567\) |
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Time = 0.28 (sec) , antiderivative size = 385, normalized size of antiderivative = 1.88 \[ \int \frac {\sec (e+f x) (c+d \sec (e+f x))^4}{(a+a \sec (e+f x))^3} \, dx=\frac {15 \, {\left ({\left (4 \, c d^{3} - 3 \, d^{4}\right )} \cos \left (f x + e\right )^{4} + 3 \, {\left (4 \, c d^{3} - 3 \, d^{4}\right )} \cos \left (f x + e\right )^{3} + 3 \, {\left (4 \, c d^{3} - 3 \, d^{4}\right )} \cos \left (f x + e\right )^{2} + {\left (4 \, c d^{3} - 3 \, d^{4}\right )} \cos \left (f x + e\right )\right )} \log \left (\sin \left (f x + e\right ) + 1\right ) - 15 \, {\left ({\left (4 \, c d^{3} - 3 \, d^{4}\right )} \cos \left (f x + e\right )^{4} + 3 \, {\left (4 \, c d^{3} - 3 \, d^{4}\right )} \cos \left (f x + e\right )^{3} + 3 \, {\left (4 \, c d^{3} - 3 \, d^{4}\right )} \cos \left (f x + e\right )^{2} + {\left (4 \, c d^{3} - 3 \, d^{4}\right )} \cos \left (f x + e\right )\right )} \log \left (-\sin \left (f x + e\right ) + 1\right ) + 2 \, {\left (15 \, d^{4} + {\left (7 \, c^{4} + 12 \, c^{3} d + 12 \, c^{2} d^{2} - 88 \, c d^{3} + 72 \, d^{4}\right )} \cos \left (f x + e\right )^{3} + 3 \, {\left (2 \, c^{4} + 12 \, c^{3} d + 12 \, c^{2} d^{2} - 68 \, c d^{3} + 57 \, d^{4}\right )} \cos \left (f x + e\right )^{2} + {\left (2 \, c^{4} + 12 \, c^{3} d + 42 \, c^{2} d^{2} - 128 \, c d^{3} + 117 \, d^{4}\right )} \cos \left (f x + e\right )\right )} \sin \left (f x + e\right )}{30 \, {\left (a^{3} f \cos \left (f x + e\right )^{4} + 3 \, a^{3} f \cos \left (f x + e\right )^{3} + 3 \, a^{3} f \cos \left (f x + e\right )^{2} + a^{3} f \cos \left (f x + e\right )\right )}} \]
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\[ \int \frac {\sec (e+f x) (c+d \sec (e+f x))^4}{(a+a \sec (e+f x))^3} \, dx=\frac {\int \frac {c^{4} \sec {\left (e + f x \right )}}{\sec ^{3}{\left (e + f x \right )} + 3 \sec ^{2}{\left (e + f x \right )} + 3 \sec {\left (e + f x \right )} + 1}\, dx + \int \frac {d^{4} \sec ^{5}{\left (e + f x \right )}}{\sec ^{3}{\left (e + f x \right )} + 3 \sec ^{2}{\left (e + f x \right )} + 3 \sec {\left (e + f x \right )} + 1}\, dx + \int \frac {4 c d^{3} \sec ^{4}{\left (e + f x \right )}}{\sec ^{3}{\left (e + f x \right )} + 3 \sec ^{2}{\left (e + f x \right )} + 3 \sec {\left (e + f x \right )} + 1}\, dx + \int \frac {6 c^{2} d^{2} \sec ^{3}{\left (e + f x \right )}}{\sec ^{3}{\left (e + f x \right )} + 3 \sec ^{2}{\left (e + f x \right )} + 3 \sec {\left (e + f x \right )} + 1}\, dx + \int \frac {4 c^{3} d \sec ^{2}{\left (e + f x \right )}}{\sec ^{3}{\left (e + f x \right )} + 3 \sec ^{2}{\left (e + f x \right )} + 3 \sec {\left (e + f x \right )} + 1}\, dx}{a^{3}} \]
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Leaf count of result is larger than twice the leaf count of optimal. 475 vs. \(2 (199) = 398\).
Time = 0.23 (sec) , antiderivative size = 475, normalized size of antiderivative = 2.32 \[ \int \frac {\sec (e+f x) (c+d \sec (e+f x))^4}{(a+a \sec (e+f x))^3} \, dx=\frac {3 \, d^{4} {\left (\frac {40 \, \sin \left (f x + e\right )}{{\left (a^{3} - \frac {a^{3} \sin \left (f x + e\right )^{2}}{{\left (\cos \left (f x + e\right ) + 1\right )}^{2}}\right )} {\left (\cos \left (f x + e\right ) + 1\right )}} + \frac {\frac {85 \, \sin \left (f x + e\right )}{\cos \left (f x + e\right ) + 1} + \frac {10 \, \sin \left (f x + e\right )^{3}}{{\left (\cos \left (f x + e\right ) + 1\right )}^{3}} + \frac {\sin \left (f x + e\right )^{5}}{{\left (\cos \left (f x + e\right ) + 1\right )}^{5}}}{a^{3}} - \frac {60 \, \log \left (\frac {\sin \left (f x + e\right )}{\cos \left (f x + e\right ) + 1} + 1\right )}{a^{3}} + \frac {60 \, \log \left (\frac {\sin \left (f x + e\right )}{\cos \left (f x + e\right ) + 1} - 1\right )}{a^{3}}\right )} - 4 \, c d^{3} {\left (\frac {\frac {105 \, \sin \left (f x + e\right )}{\cos \left (f x + e\right ) + 1} + \frac {20 \, \sin \left (f x + e\right )^{3}}{{\left (\cos \left (f x + e\right ) + 1\right )}^{3}} + \frac {3 \, \sin \left (f x + e\right )^{5}}{{\left (\cos \left (f x + e\right ) + 1\right )}^{5}}}{a^{3}} - \frac {60 \, \log \left (\frac {\sin \left (f x + e\right )}{\cos \left (f x + e\right ) + 1} + 1\right )}{a^{3}} + \frac {60 \, \log \left (\frac {\sin \left (f x + e\right )}{\cos \left (f x + e\right ) + 1} - 1\right )}{a^{3}}\right )} + \frac {6 \, c^{2} d^{2} {\left (\frac {15 \, \sin \left (f x + e\right )}{\cos \left (f x + e\right ) + 1} + \frac {10 \, \sin \left (f x + e\right )^{3}}{{\left (\cos \left (f x + e\right ) + 1\right )}^{3}} + \frac {3 \, \sin \left (f x + e\right )^{5}}{{\left (\cos \left (f x + e\right ) + 1\right )}^{5}}\right )}}{a^{3}} + \frac {c^{4} {\left (\frac {15 \, \sin \left (f x + e\right )}{\cos \left (f x + e\right ) + 1} - \frac {10 \, \sin \left (f x + e\right )^{3}}{{\left (\cos \left (f x + e\right ) + 1\right )}^{3}} + \frac {3 \, \sin \left (f x + e\right )^{5}}{{\left (\cos \left (f x + e\right ) + 1\right )}^{5}}\right )}}{a^{3}} + \frac {12 \, c^{3} d {\left (\frac {5 \, \sin \left (f x + e\right )}{\cos \left (f x + e\right ) + 1} - \frac {\sin \left (f x + e\right )^{5}}{{\left (\cos \left (f x + e\right ) + 1\right )}^{5}}\right )}}{a^{3}}}{60 \, f} \]
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Time = 0.38 (sec) , antiderivative size = 374, normalized size of antiderivative = 1.82 \[ \int \frac {\sec (e+f x) (c+d \sec (e+f x))^4}{(a+a \sec (e+f x))^3} \, dx=-\frac {\frac {120 \, d^{4} \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )}{{\left (\tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )^{2} - 1\right )} a^{3}} - \frac {60 \, {\left (4 \, c d^{3} - 3 \, d^{4}\right )} \log \left ({\left | \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right ) + 1 \right |}\right )}{a^{3}} + \frac {60 \, {\left (4 \, c d^{3} - 3 \, d^{4}\right )} \log \left ({\left | \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right ) - 1 \right |}\right )}{a^{3}} - \frac {3 \, a^{12} c^{4} \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )^{5} - 12 \, a^{12} c^{3} d \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )^{5} + 18 \, a^{12} c^{2} d^{2} \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )^{5} - 12 \, a^{12} c d^{3} \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )^{5} + 3 \, a^{12} d^{4} \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )^{5} - 10 \, a^{12} c^{4} \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )^{3} + 60 \, a^{12} c^{2} d^{2} \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )^{3} - 80 \, a^{12} c d^{3} \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )^{3} + 30 \, a^{12} d^{4} \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )^{3} + 15 \, a^{12} c^{4} \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right ) + 60 \, a^{12} c^{3} d \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right ) + 90 \, a^{12} c^{2} d^{2} \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right ) - 420 \, a^{12} c d^{3} \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right ) + 255 \, a^{12} d^{4} \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )}{a^{15}}}{60 \, f} \]
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Time = 13.54 (sec) , antiderivative size = 195, normalized size of antiderivative = 0.95 \[ \int \frac {\sec (e+f x) (c+d \sec (e+f x))^4}{(a+a \sec (e+f x))^3} \, dx=\frac {\mathrm {tan}\left (\frac {e}{2}+\frac {f\,x}{2}\right )\,\left (\frac {3\,{\left (c-d\right )}^4}{4\,a^3}+\frac {3\,{\left (c^2-d^2\right )}^2}{2\,a^3}-\frac {2\,\left (c+d\right )\,{\left (c-d\right )}^3}{a^3}\right )}{f}+\frac {{\mathrm {tan}\left (\frac {e}{2}+\frac {f\,x}{2}\right )}^3\,\left (\frac {{\left (c-d\right )}^4}{6\,a^3}-\frac {\left (c+d\right )\,{\left (c-d\right )}^3}{3\,a^3}\right )}{f}-\frac {2\,d^4\,\mathrm {tan}\left (\frac {e}{2}+\frac {f\,x}{2}\right )}{f\,\left (a^3\,{\mathrm {tan}\left (\frac {e}{2}+\frac {f\,x}{2}\right )}^2-a^3\right )}+\frac {{\mathrm {tan}\left (\frac {e}{2}+\frac {f\,x}{2}\right )}^5\,{\left (c-d\right )}^4}{20\,a^3\,f}+\frac {2\,d^3\,\mathrm {atanh}\left (\mathrm {tan}\left (\frac {e}{2}+\frac {f\,x}{2}\right )\right )\,\left (4\,c-3\,d\right )}{a^3\,f} \]
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